Program to cheque enter number is even or odd using switch case in C-language

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#include<stdio.h>
int main()
{
    int x;
    printf("Enter the number\n");
    scanf("%d",&x);
    switch(x%2)
    {
        case 0:
        printf("Enter numbet is even");
        break;
        default:
        printf("Enter number is odd");
        break;
       
    }
}

OUTPUT
Enter the number
90
Enter number is even

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