Program to implement a calculator by switch case in C-language

Program to implement a calculator by switch case in C-language

                             Method-1
#include<stdio.h>
int main()
{
float x,y;
char ch;
printf("Enter first number\n");
scanf("%f",&x);
printf("Enter second number\n");
scanf("%f",&y);
printf("Enter\n+ for add\n- for sub\n* for multiply\n/ for div\n");
scanf("\n%c",&ch);
switch(ch)
{
case '+':
printf("Add=%f",(x+y));
break;
case '-':
printf("Sub=%f",(x-y));
break;
case '*':
printf("Multiply=%f",(x*y));
break;
case '/':
printf("Div=%f",(x/y));
break;
default:
printf("Invalid input!!");
}

}

                                 Method-2
#include<stdio.h>
int main()
{
float x,y;
char ch;
printf("Enter first number\n");
scanf("%f",&x);
printf("Enter second number\n");
scanf("%f",&y);
printf("Enter\n1 for add\n2 for sub\n3 for multiply\n4 for div\n");
scanf("\n%c",&ch);
switch(ch)
{
case '1':
printf("Add=%f",(x+y));
break;
case '2':
printf("Sub=%f",(x-y));
break;
case '3':
printf("Multiply=%f",(x*y));
break;
case '4':
printf("Div=%f",(x/y));
break;
default:
printf("Invalid input!!");
}
}

OUTPUT
Enter first number
7
Enter second number
1
Enter
1 for add
2 for sub
3 for multiply
4 for div
1
Add=8.000000

This program give you a rough idea about calculator working.And this program is also famous problem of switch case.

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