Program to cheque give character is vowel or not using switch case in C-language

-
                         Method-1

#include<stdio.h>
int main()
{
    char ch;
    printf("Enter the character\n");
    scanf("%c",&ch);
    switch(ch)
    {
        case'a':
        printf("Enter character is vowel");
        break;
        case'e':
        printf("Enter character is vowel");
        break;
        case'i':
        printf("Enter character is vowel");
        break;
        case'o':
        printf("Enter character is vowel");
        break;
        case'u':
        printf("Enter character is vowel");
        break;
        case'A':
        printf("Enter character is vowel");
        break;
        case'E':
        printf("Enter character is vowel");
        break;
        case'I':
        printf("Enter character is vowel");
        break;
        case'O':
        printf("Enter character is vowel");
        break;
        case'U':
        printf("Enter character is vowel");
        break;
        default:
        printf("Enter character is not vowel");
    }
}
                           Method-2
#include<stdio.h>
int main()
{
    char ch;
    printf("Enter the character\n");
    scanf("%c",&ch);
    switch(ch)
    {
        case'a':
        case'e':
        case'i':
        case'o':
        case'u':
        case'A':
        case'E':
        case'I':
        case'O':
        case'U':
        printf("Enter character is vowel");
        break;
        default:
        printf("Enter character is not vowel");
    }
}

OUTPUT
Enter the character
e
Enter character is vowel

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